CBSE • Class 11 • Physics
Motion in a Plane
Vectors, projectile motion, and uniform circular motion.
Chapter 3
Verified Curriculum Topic
What is Motion in a Plane?
Vectors, projectile motion, and uniform circular motion.
Motion in a Plane matters because it connects theory, equations, and real physical behaviour. At Class 11 level, students are typically expected to explain concepts precisely, apply laws correctly, and interpret numerical or experimental questions with confidence.
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Summary
The One Thing
Motion in a plane is analysed by representing physical quantities as vectors and resolving them into perpendicular components. This allows projectile motion and circular motion to be treated using separate horizontal and vertical equations while accounting for changes in both magnitude and direction.
Reactions, Processes and Experiments
| What happens | Equation or process | What you observe | Type |
|---|---|---|---|
| A vector is expressed in terms of its perpendicular components along the coordinate axes. | A = Ax i + Ay j, where Ax = A cos theta and Ay = A sin theta. | — | Vector resolution |
| Two vectors are combined to determine their resultant magnitude. | R = sqrt(A^2 + B^2 + 2AB cos theta). | — | Vector addition |
| The scalar product of two vectors is calculated. | A dot B = AB cos theta. | The result is a scalar quantity. | Scalar product |
| The vector product of two vectors is calculated. | A cross B = AB sin theta n, where n is perpendicular to the plane containing A and B. | The result is a vector perpendicular to the plane containing A and B; its direction is found using the right-hand rule. | Vector product |
| An object is projected with initial speed u at angle theta and its velocity is resolved into horizontal and vertical components. | ux = u cos theta and uy = u sin theta. | — | Projectile motion |
| A projectile moves horizontally with constant velocity. | x = (u cos theta)t. | Horizontal velocity remains constant. | Uniform horizontal motion |
| A projectile moves vertically under constant downward acceleration. | y = (u sin theta)t - (1/2)gt^2. | Vertical velocity changes because of gravity. | Uniformly accelerated vertical motion |
| The horizontal and vertical velocity components of a projectile are determined during flight. | vx = u cos theta and vy = u sin theta - gt. | The horizontal component remains constant, while the vertical component changes with time. | Projectile motion |
| The path of an ideal projectile is determined. | y = x tan theta - gx^2/(2u^2 cos^2 theta). | The trajectory is a parabola. | Projectile trajectory |
| A projectile lands at the same height from which it was projected, and its flight time is determined. | T = 2u sin theta/g. | — | Projectile motion |
| A projectile reaches its greatest vertical displacement above the launch level. | H = u^2 sin^2 theta/(2g). | The vertical velocity is zero at maximum height. | Projectile motion |
| A projectile lands at the same height from which it was projected, and its horizontal range is determined. | R = u^2 sin 2theta/g. | — | Projectile motion |
| The projection angle is varied for projectiles landing at the same height. | The range is maximum when the angle of projection is 45 degrees, provided air resistance is neglected and the launch and landing levels are the same. | Maximum horizontal range occurs at 45 degrees. | Projectile motion |
| An object is projected horizontally from height h with horizontal speed u. | t = sqrt(2h/g), and horizontal distance is x = u sqrt(2h/g). | The object has horizontal motion while falling vertically to the ground. | Horizontal projection |
| An object moves around a circular path at constant speed. | a_c = v^2/r = r omega^2. | Acceleration is directed toward the centre of the circle. | Uniform circular motion |
| The inward force required to maintain circular motion is determined. | F_c = mv^2/r = mr omega^2. | The net force acts toward the centre. | Centripetal force |
| The time period and frequency of circular motion are related to speed, radius and angular velocity. | T = 2pi r/v = 2pi/omega, and frequency is f = 1/T. | — | Uniform circular motion |
| The acceleration due to gravity near Earth's surface is used in calculations. | g = 9.8 m/s^2, often approximated as 10 m/s^2 in numerical problems. | — | Gravitational acceleration |
Key Terms
- Scalar: A physical quantity described only by magnitude, such as distance, speed, and time.
- Vector: A physical quantity described by both magnitude and direction, such as displacement, velocity, and acceleration.
- Position Vector: A vector drawn from the origin to the position of a particle, usually written as r = xi + yj.
- Displacement Vector: The change in position of an object, given by the final position vector minus the initial position vector.
- Unit Vector: A vector having magnitude one and pointing in a specified direction; i, j, and k represent unit vectors along the x-, y-, and z-axes.
- Vector Addition: The process of finding the resultant vector using the triangle law or parallelogram law.
- Vector Components: The parts of a vector along chosen coordinate axes. A vector A making angle theta with the x-axis has components Ax = A cos theta and Ay = A sin theta.
- Projectile: An object projected into the air that moves under the influence of gravity alone, neglecting air resistance.
- Projectile Motion: Two-dimensional motion in which horizontal motion is uniform and vertical motion has constant downward acceleration g.
- Trajectory: The path followed by a moving object. The trajectory of an ideal projectile is a parabola.
- Range: The horizontal distance travelled by a projectile before it returns to the same level from which it was projected.
- Uniform Circular Motion: Motion along a circular path with constant speed, while the velocity changes continuously because its direction changes.
- Centripetal Acceleration: The inward acceleration required for circular motion, directed toward the centre of the circle.
- Angular Velocity: The rate of change of angular displacement, represented by omega and related to linear speed by v = r omega.
Easily Confused
- Scalar and vector: A scalar has magnitude only, whereas a vector has both magnitude and direction.
- Speed and velocity: Speed is a scalar, whereas velocity is a vector; in uniform circular motion, speed remains constant but velocity changes because its direction changes.
- Horizontal and vertical projectile motion: Horizontal motion is uniform, while vertical motion has constant downward acceleration g.
- Centripetal acceleration and centripetal force: Centripetal acceleration is the inward acceleration, whereas centripetal force is the net inward force producing that acceleration.
- Centripetal force and a separate force type: Centripetal force is not a new type of force; it is provided by forces such as tension, friction, gravity, or the normal reaction.
- Time of flight and time period: Time of flight refers to a projectile’s motion, whereas the time period is the time for one complete revolution in circular motion.
- Range and maximum height: Range is the horizontal distance travelled, whereas maximum height is the greatest vertical displacement above the launch level.
- General projection and horizontal projection: General projectile motion begins with components u cos theta and u sin theta, whereas horizontal projection has an initial vertical component of zero and is specified by height h and horizontal speed u.
What Gets Asked
- Resolve a vector into perpendicular components using Ax = A cos theta and Ay = A sin theta. Marks are lost by interchanging the sine and cosine components or failing to identify the angle’s reference axis.
- Calculate the resultant of two vectors using R = sqrt(A^2 + B^2 + 2AB cos theta), or distinguish the scalar product from the vector product. Marks are lost by treating A dot B as a vector or omitting the perpendicular direction n from A cross B.
- Derive or apply projectile equations for displacement, velocity, trajectory, time of flight, maximum height and range. Marks are lost by using same-level formulas when the launch and landing levels are not the same, or by confusing horizontal and vertical components.
- Determine the angle for maximum projectile range. The required condition is 45 degrees only when air resistance is neglected and the launch and landing levels are the same.
- Solve horizontal-projection problems using t = sqrt(2h/g) and x = u sqrt(2h/g). Marks are lost by applying the angled-projectile time-of-flight formula instead.
- Explain uniform circular motion and calculate a_c, F_c, T or f. Marks are lost by claiming that acceleration is zero because speed is constant, or by treating centripetal force as a separate fundamental type of force.
Flashcards
Quick quiz
Which statement correctly describes a vector?
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Common exam prompts
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- Explain a diagram, graph, or experiment related to Motion in a Plane.
- Distinguish between conceptual understanding and memorised formula use in this chapter.
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Quick answers students usually need
What is Motion in a Plane in CBSE Class 11 Physics?
Vectors, projectile motion, and uniform circular motion.
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