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CBSEClass 11Physics

System of Particles and Rotational Motion

Centre of mass, torque, angular momentum, and rotational dynamics.

Chapter 6

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What is System of Particles and Rotational Motion?

Centre of mass, torque, angular momentum, and rotational dynamics.

System of Particles and Rotational Motion matters because it connects theory, equations, and real physical behaviour. At Class 11 level, students are typically expected to explain concepts precisely, apply laws correctly, and interpret numerical or experimental questions with confidence.

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Summary

The One Thing

The motion of a system or rotating body can be analysed by separating translational motion of its centre of mass from rotational motion about an axis. Torque, moment of inertia and angular momentum provide the rotational counterparts of force, mass and linear momentum, while conservation laws simplify systems with no external force or torque.

Reactions, Processes and Experiments

What happensEquation or processWhat you observeType
The position of the centre of mass of two particles is determined from their masses and position vectors.rcm = (m1r1 + m2r2)/(m1 + m2)The centre of mass lies closer to the particle with the greater mass.Centre-of-mass calculation
The position of the centre of mass of a system is determined from all particle masses and position vectors.rcm = (Σmi ri)/(Σmi)The result represents the mass-weighted average position of the system.Centre-of-mass calculation
The centre-of-mass velocity is determined from the velocities of the particles.vcm = (Σmi vi)/(Σmi)Internal motions may cancel, leaving the velocity of the system’s centre of mass.Translational motion of a system
The centre-of-mass acceleration is determined by the net external force.acm = Fext/MInternal forces do not alter the motion of the centre of mass; only external forces do so.Newtonian motion of a system
The total linear momentum of a system is related to the centre-of-mass velocity.P = MvcmThe total momentum is the vector sum of the momenta of all particles.Linear momentum
The total linear momentum of an isolated system remains unchanged.For an isolated system, total linear momentum remains constant.Momentum before and after an interaction is equal.Conservation of linear momentum
A force produces a turning effect about a point or axis.τ = r × FThe turning effect depends on the position vector and the applied force.Torque
The magnitude of torque depends on the angle between the position vector and the force.τ = rF sinθ = F × perpendicular distanceTorque is maximum when the force is perpendicular to the position vector and zero when its line of action passes through the axis.Torque
Angular momentum is determined for a particle relative to an origin or axis.L = r × pAngular momentum depends on the position vector and linear momentum.Angular momentum
The magnitude of a particle’s angular momentum is determined by the angle between position and momentum vectors.L = rp sinθAngular momentum is zero when the position vector and momentum are parallel.Angular momentum
A rigid body rotating about a fixed axis has angular momentum proportional to angular velocity.L = IωA larger moment of inertia gives greater angular momentum at the same angular velocity.Rotational dynamics
Net torque produces angular acceleration.τnet = IαA larger moment of inertia makes a body more resistant to changes in rotational motion.Rotational form of Newton’s second law
The moment of inertia of a collection of particles depends on their masses and distances from the axis.I = Σmi ri²Particles farther from the axis contribute more strongly to rotational inertia.Moment of inertia
The moment of inertia about an axis parallel to an axis through the centre of mass is determined using the distance between the axes.I = Icm + Md²Moving the axis away from the centre of mass increases the moment of inertia.Parallel-axis theorem
The moment of inertia of a plane lamina about an axis perpendicular to its plane is related to the moments about two perpendicular axes in the plane.Iz = Ix + IyThe perpendicular-axis moment equals the sum of the two in-plane moments.Perpendicular-axis theorem
Rotational kinetic energy is associated with angular motion.Krot = 1/2 Iω²Rotational kinetic energy increases with moment of inertia and with the square of angular velocity.Rotational kinetic energy
A constant torque does work through an angular displacement.W = τθWork increases with torque and angular displacement.Rotational work
Torque produces rotational power.P = τωPower increases when either torque or angular velocity increases.Rotational power
Torque acting over a time interval changes angular momentum.angular impulse = τΔt = change in angular momentumThe change in angular momentum equals the angular impulse.Angular impulse
Angular momentum remains unchanged when the net external torque is zero.Li = LfAngular speed can change when mass distribution changes, while total angular momentum remains constant.Conservation of angular momentum
A body rolls without slipping through simultaneous translational and rotational motion.vcm = RωThe point of contact is instantaneously at rest relative to the surface.Pure rolling
The linear and angular accelerations of a body rolling without slipping are related.acm = RαTranslational acceleration and angular acceleration remain linked by the radius.Rolling motion
The kinetic energy of a rolling body contains translational and rotational components.K = 1/2 Mvcm² + 1/2 Icmω²Both motion of the centre of mass and rotation contribute to total kinetic energy.Rolling kinetic energy
The moment of inertia of a thin ring about its central axis is determined by its mass and radius.I = MR²All mass is effectively distributed at the same radius from the axis.Standard moment of inertia
The moment of inertia of a disc or solid cylinder about its central axis is determined by its mass and radius.I = 1/2 MR²The value is less than that of a thin ring with the same mass and radius because some mass lies closer to the axis.Standard moment of inertia
The moment of inertia of a solid sphere about a diameter is determined by its mass and radius.I = 2/5 MR²The mass is distributed throughout the sphere relative to the diameter.Standard moment of inertia
The moment of inertia of a hollow sphere about a diameter is determined by its mass and radius.I = 2/3 MR²The distribution of mass produces a different rotational inertia from a solid sphere.Standard moment of inertia
The moment of inertia of a rod about an axis through its centre is determined by its mass and length.I = 1/12 ML²The rod has a smaller moment of inertia about its centre than about an end.Standard moment of inertia
The moment of inertia of a rod about an axis through one end is determined by its mass and length.I = 1/3 ML²Moving the axis from the centre to the end increases the moment of inertia.Standard moment of inertia
The centre of mass of a uniform symmetrical body is located at its geometrical centre.The centre of mass of a uniform symmetrical body lies at its geometrical centre.The geometrical centre is the balance point for the uniform symmetrical body.Centre of mass
In uniform circular motion, angular speed remains constant while the direction of linear velocity changes.In uniform circular motion, angular speed is constant but the direction of linear velocity changes continuously.The speed is constant, but the velocity is not constant because its direction changes.Circular motion
Rotational equilibrium requires no net external torque.The net external torque on a body is zero, so its angular acceleration is zero.The body has no angular acceleration.Rotational equilibrium
Complete equilibrium requires both translational and rotational balance.For equilibrium, both the net external force and the net external torque must be zero.Neither the centre of mass accelerates nor the body undergoes angular acceleration.Mechanical equilibrium

Key Terms

  • System of Particles: A collection of two or more particles considered together for studying their motion and interactions.
  • Centre of Mass: The point at which the entire mass of a system may be considered concentrated for analysing translational motion.
  • Centre of Mass of Two Particles: For masses m1 and m2 at positions r1 and r2, the centre-of-mass position is rcm = (m1r1 + m2r2)/(m1 + m2).
  • Centre of Mass of a System: For particles with masses mi and position vectors ri, rcm = (Σmi ri)/(Σmi).
  • Linear Momentum: The product of mass and velocity; for a system, total momentum is the vector sum of the momenta of all particles.
  • Torque: The turning effect of a force about a point or axis, given by τ = r × F, with magnitude τ = rF sinθ.
  • Moment Arm: The perpendicular distance from the axis of rotation to the line of action of the force.
  • Angular Momentum: The rotational equivalent of linear momentum; for a particle, L = r × p, and for a rigid body rotating about a fixed axis, L = Iω.
  • Moment of Inertia: The rotational inertia of a body, defined for particles as I = Σmi ri² and dependent on the mass distribution relative to the axis.
  • Radius of Gyration: The distance k from the axis at which the entire mass could be assumed concentrated to produce the same moment of inertia; I = Mk².
  • Angular Displacement: The angle through which a body rotates, usually measured in radians.
  • Angular Velocity: The rate of change of angular displacement, given by ω = dθ/dt.
  • Angular Acceleration: The rate of change of angular velocity, given by α = dω/dt.
  • Rigid Body: An ideal body in which the distance between every pair of particles remains constant during motion.
  • Rotational Equilibrium: A state in which the net external torque on a body is zero, so its angular acceleration is zero.
  • Rolling Motion: Combined translational and rotational motion in which a body rolls without slipping when vcm = Rω.

Easily Confused

  • Force and torque: Force governs translational motion, whereas torque is the turning effect of a force and governs rotational motion.
  • Mass and moment of inertia: Mass measures resistance to translational acceleration, whereas moment of inertia measures resistance to angular acceleration and depends on mass distribution relative to the axis.
  • Linear momentum and angular momentum: Linear momentum is p = mv, whereas angular momentum is L = r × p or L = Iω for a rigid body about a fixed axis.
  • Centre of mass and geometrical centre: The centre of mass is determined by mass distribution; it coincides with the geometrical centre only for a uniform symmetrical body.
  • Rotational equilibrium and complete equilibrium: Rotational equilibrium requires zero net external torque, whereas complete equilibrium requires both zero net external force and zero net external torque.
  • Angular speed and linear velocity in uniform circular motion: Angular speed remains constant, but the direction of linear velocity changes continuously.
  • Pure rolling and rotation alone: Pure rolling combines translation and rotation and satisfies vcm = Rω; rotation alone does not require this condition.
  • Internal and external forces: Internal forces cannot change the motion of the centre of mass, whereas only external forces can do so.
  • Thin ring and disc or solid cylinder: For the same mass and radius, a thin ring has I = MR², whereas a disc or solid cylinder has I = 1/2 MR².
  • Rod about its centre and rod about one end: The moments of inertia are I = 1/12 ML² and I = 1/3 ML², respectively.

What Gets Asked

  • Calculate the centre of mass of two particles or of a system using rcm = (m1r1 + m2r2)/(m1 + m2) or rcm = (Σmi ri)/(Σmi). Marks are lost by failing to use mass-weighted positions.
  • Determine the motion of a system’s centre of mass using vcm = (Σmi vi)/(Σmi), P = Mvcm or acm = Fext/M. The key slip is attributing a change in centre-of-mass motion to internal forces.
  • Calculate torque using τ = r × F or τ = rF sinθ, and identify when torque is maximum or zero. Marks are lost by using the distance to the point of application instead of the perpendicular distance to the line of action.
  • Apply rotational dynamics through τnet = Iα, rotational kinetic energy Krot = 1/2 Iω², work W = τθ or power P = τω. The common error is substituting mass for moment of inertia.
  • Use the parallel-axis theorem, perpendicular-axis theorem and standard moments of inertia. Marks are lost by selecting the wrong axis or confusing the values for a thin ring, disc or solid cylinder, sphere or rod.
  • Apply conservation of angular momentum using Li = Lf when the net external torque is zero, including cases in which mass distribution or angular speed changes. The key condition must not be omitted.
  • Analyse rolling motion using vcm = Rω, acm = Rα and K = 1/2 Mvcm² + 1/2 Icmω². Marks are lost by including only translational or only rotational kinetic energy.

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  • Explain the core principle behind System of Particles and Rotational Motion in clear scientific language.
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What is System of Particles and Rotational Motion in CBSE Class 11 Physics?

Centre of mass, torque, angular momentum, and rotational dynamics.

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